I am not sure if people have given this much thought, but I've noticed from having watched the picks and statistics from each weeks drawings from both super 7 and 6/49. Although super 7 is only drawn once a week, it seems that the jackpot doesn't seem to reach to the same size as 6/49 usually does. Once in a while, it goes above 12million..but otherwise people tend to win the jackpot before that can happen. And comparing the amounts sold in tickets, super 7 still manages to give away more 6/6 jackpots.
The funny thing is that when you compare 6/49's odds of winning ( 1 in 13,983,816 ) to that of super 7 ( 1 in 20,963,833 ), the opposite should be true.

What could be the answer to this? could it be that 6/49 always reaches higher jackpots because it is played twice as often as super 7? so the odds allow it more often for people not to win the jackpot? or is it simply that super 7's odds of winning a free ticket and smaller prize payouts have a higher precentage?...meaning that people will either get to play again for free or will reinvest in more tickets with the smaller winnings?

Anybody have any ideas?

i think its mostly cost vs number of lines.

You can divide the odds by three for super 7 as you get that many lines per $2 spent, therefore 3x as many lines will be taken for each draw. Not to mention everything else you mentioned !

well actually the odds I mentioned are per 2 dollars played with both games. As you get 3 selections with Super 7 versus only one with 6/49, the actual odds of winning super 7 per selection is somewhere in the vicinity of 1 in 60,000,000.
(I think...not 100% sure)

So my question again is, might it be those different factors I was mentioning?

yea, i actually looked into it, and its

3 in 20,963,833 for super 7.... on a $2 ticket

hahah so the odds are still quite staggering! All i can really think of is more tickets are sold for the super 7 because of the 'value' and the extra 3 days of sales per draw.


I noticed that on the last super 7 draw there were 1.23 milllion free tickets [3/7] and 280,000+ $10 winners [4/7, 3/7+B]

VS

200,000+ winners of $5 AND $10 on the 6/49 --- 8 Million dollar draw at that!

if you multiply by the odds of winning those prizes, you'll figure out how much more Super 7 sells... i bet its a pretty big difference.

the ODDS of winning in super 7 are 1 in 60-odd million, a simple n-factorial as everyone here already knows.....the CHANCES of winning, with the purchase of 3 seperate entries, are 1 in 20-odd million.....BC lottery and perhaps other provinces across the country list the CHANCES, because the numbers look better from the consumer standpoint........CHANCES of winning work like this: if you buy one set of 7 numbers, the ODDS and CHANCES are identical...if you buy 2 sets of 7 numbers, the ODDS remain the same for each entry, but the CHANCES of winning are now twice as good, at 1 in 30-some odd million...the numbers then get progressively better as far as CHANCES are concerned....if you buy 3 sets of numbers, the CHANCES are the advertised 1 in 20-odd million.....if you buy all 60-some odd million sets of 7 numbers, the CHANCES increase to 1 in 1, and you are a winner for sure.....buying along the way, the CHANCES chances of winning remain at their respective numbers as long as each 7 number entry consists of a different set of 7 numbers......if you buy all possible sets of 7 numbers except for one, the ODDS of winning still remain at 60-odd million to 1 for each set of numbers, although the CHANCES of winning are now pretty good, with only 1 possible combination of 60-odd million possibilities not being in your possession..............