Numbers can communicate to you if you talk to them and ask them questions. In many cultures throwing the bones is a way of forecasting the future. In South Africa a sangoma is a person who indulges in this type of practice. For fun click on the link and meet Lazarous Bondiso, a fun online sangoma.
[url]http://www.lottofun.co.za/wacky/wacky.asp[/url]

Now I propose something more serious. I have asked number pairs questions questions and they have communicated to me. I have achieved some great results sometimes. I am still learning their language which is statistical mathematics with a twist. What I have done is to turn MDIED into a statistical sangoma where number pairs talk to you if you ask them the right questions. Sometimes they talk rubbish and other times they are extremely accurate. I call this method Sangoma and will initially discuss it in regards to the 49's lottery but it can be ported to any other type of lottery. It requires some effort. You will need to download MDIED and find your way around it. Also you will need a little computer programme to convert real draws into specific formats. Most important you will need to re-programme your brain to look at supposedly random number pairs in a different way. If you are not prepared to put in the necessary effort then turn away and go back into wheeling numbers and lose. Later on I will discuss Sangoma in more detail.

Here we have a skip chart for the alpha file. Each alpha number represents 2 real numbers except alpha24 which represents 3 numbers. Now we know on average 50% of the time 75% of those alpha numbers will hit in 4 draws. If I had 24 tennis balls and wrote a number pair on each and threw all the balls into the lawn in the garden and asked my Rhodesian Ridgeback dog,Sam, to fetch, he will be spot on 75% of the time in predicting which pair will hit in the next 4 draws. Surely we can do better than Sam. Can we push the strike rate to 80%, 90% or even 100%.I mean we are smarter than Sam, Aren't we?
Firstly we convert the real numbers into the alpha format and place the alpha numbers into MDIED. Mdied runs a stats report snd you see it below. Now we will talk to a number and using the sangoma technique will try to find an alpha number that has no chance of failing to hit in the next 4 draws.
Look at alpha15 and converse with it. It will tell you the following. I am sitting on the skip of 5 and look at my history(herstory for the feminists). I have hit 56 times in the last 200 draws-that is 28% strike rate.Taking the parameter that I must hit in the next 4 draws(in other words I must hit by my 9th skip)-look at my past performance. 53 out of 56 hits have happened within 9 skips.That is a 95% strike rate within 9 skips. I am obviously a worth fellow to bet on for the next 4 draws or less. This is an illustration in having an imaginary conversation with a number pair. Each pair has a story to tell you, but you have to listen.

refer to previous post for explanation. I have had to shorten it by cutting off the last 6 alpha numbers.

alpha-7 SKIP Chart
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* alpha # 1 * Hits: 59
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* Skips >>>>> 0 0 2 1 12 0 5 3 1 0 0 1 1 5 2 0 1 2 6 2 6 0 1 0 0 3 2 1 3 2 1 0 2 1 1 0 7 3 0 0 3 0 5 5 4 10 8 2 0 2 2 10 0 3 0 1 5 2 2 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 4 5 5 5 5 5 6 6 7 8 10 10 12 ** Skip Median: 2
* alpha # 2 * Hits: 54
------------------------
* Skips >>>>> 3 0 12 10 0 10 3 7 2 0 1 2 1 1 1 2 4 3 3 0 3 3 3 5 2 4 1 1 1 3 1 0 0 2 1 0 3 2 3 1 0 2 9 12 2 4 0 1 1 4 0 1 0 1 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 4 4 4 4 5 7 9 10 10 12 12 ** Skip Median: 2
* alpha # 3 * Hits: 55
------------------------
* Skips >>>>> 2 5 0 3 1 0 2 0 1 2 0 11 0 1 4 0 3 2 2 1 7 0 2 3 2 1 1 1 2 1 1 7 0 2 1 6 6 13 2 0 1 2 0 0 3 2 8 0 0 10 3 4 9 1 1 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 4 4 5 6 6 7 7 8 9 10 11 13 ** Skip Median: 2
* alpha # 4 * Hits: 62
------------------------
* Skips >>>>> 6 0 0 5 1 1 0 4 0 0 0 2 2 9 0 1 7 0 3 3 2 7 1 0 7 0 6 6 1 1 0 1 1 4 3 0 0 3 1 4 2 1 0 0 1 1 0 0 3 2 3 1 0 0 8 2 11 0 1 0 3 4 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 3 3 3 3 4 4 4 4 5 6 6 6 7 7 7 8 9 11 ** Skip Median: 1
* alpha # 5 * Hits: 54
------------------------
* Skips >>>>> 4 0 11 5 0 6 2 0 5 2 0 2 2 9 1 14 0 7 0 4 2 1 4 3 1 1 1 2 2 2 0 1 0 3 5 1 1 13 1 4 1 0 0 3 0 3 4 0 10 1 0 0 1 0 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 3 3 3 3 4 4 4 4 4 5 5 5 6 7 9 10 11 13 14 ** Skip Median: 1
* alpha # 6 * Hits: 48
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* Skips >>>>> 4 2 6 1 0 11 0 6 4 1 4 5 0 7 0 1 2 11 8 4 14 0 2 0 0 1 0 1 6 10 1 1 1 2 0 2 3 0 0 0 2 2 4 14 0 1 1 7 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 3 4 4 4 4 4 5 6 6 6 7 7 8 10 11 11 14 14 ** Skip Median: 2
* alpha # 7 * Hits: 59
------------------------
* Skips >>>>> 1 1 1 0 2 0 2 0 6 0 7 5 0 4 0 10 4 0 1 4 1 2 0 6 0 1 5 0 1 0 1 5 2 0 4 1 2 0 1 4 0 7 0 18 0 4 0 5 2 3 0 0 2 0 1 2 2 6 5 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 3 4 4 4 4 4 4 5 5 5 5 5 6 6 6 7 7 10 18 ** Skip Median: 1
* alpha # 8 * Hits: 48
------------------------
* Skips >>>>> 3 4 1 2 0 2 0 2 1 0 1 2 1 2 0 1 7 7 3 6 16 1 6 1 7 5 0 0 0 13 5 0 8 6 3 0 0 0 1 1 5 11 0 3 5 5 3 2 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 3 3 4 5 5 5 5 5 6 6 6 7 7 7 8 11 13 16 ** Skip Median: 2
* alpha # 9 * Hits: 49
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* Skips >>>>> 9 0 2 2 3 3 0 2 7 3 0 3 0 0 0 0 5 9 0 10 8 8 0 0 6 2 1 3 3 4 3 3 1 3 8 4 5 5 3 0 0 0 7 3 3 1 1 2 4 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 3 3 4 4 4 5 5 5 6 7 7 8 8 8 9 9 10 ** Skip Median: 3
* alpha # 10 * Hits: 60
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* Skips >>>>> 0 0 3 0 0 1 2 0 4 2 5 3 6 1 2 2 1 1 0 1 0 1 2 0 4 1 1 2 0 3 2 1 3 2 1 2 3 3 3 1 1 2 4 4 5 0 3 1 2 8 5 2 3 2 4 1 7 1 0 15 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 4 4 4 4 4 5 5 5 6 7 8 15 ** Skip Median: 2
* alpha # 11 * Hits: 47
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* Skips >>>>> 2 3 1 2 0 2 0 2 2 1 8 5 1 10 5 3 2 0 4 2 18 2 17 4 7 2 4 1 2 2 2 1 0 0 4 0 3 3 4 1 6 2 0 0 4 7 2 * Sorted Skips: 0 0 0 0 0 0 0 0 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 4 4 4 4 4 4 5 5 6 7 7 8 10 17 18 ** Skip Median: 2
* alpha # 12 * Hits: 45
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* Skips >>>>> 1 1 0 2 12 0 1 3 9 1 0 1 6 0 2 3 5 2 7 0 0 5 1 0 5 2 3 4 2 1 9 5 8 1 3 2 0 0 2 7 28 0 4 1 5 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 4 4 5 5 5 5 5 6 7 7 8 9 9 12 28 ** Skip Median: 2
* alpha # 13 * Hits: 63
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* Skips >>>>> 2 8 3 4 2 2 2 0 4 3 0 2 1 3 0 0 0 1 4 2 1 0 1 0 0 0 8 1 1 4 1 1 2 3 0 0 4 1 1 0 2 2 1 5 1 6 0 5 4 10 1 1 0 0 1 1 4 3 0 9 0 4 5 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 3 3 3 3 3 4 4 4 4 4 4 4 4 5 5 5 6 8 8 9 10 ** Skip Median: 1
* alpha # 14 * Hits: 54
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* Skips >>>>> 4 0 6 3 1 3 8 0 2 0 8 10 4 1 0 6 3 2 0 0 3 2 0 0 5 1 6 8 1 1 8 1 0 1 3 1 3 0 2 6 0 2 1 5 10 0 0 0 9 0 0 4 2 0 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 3 3 3 4 4 4 5 5 6 6 6 6 8 8 8 8 9 10 10 ** Skip Median: 2
* alpha # 15 * Hits: 56
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* Skips >>>>> 5 4 14 0 1 1 2 0 1 9 0 0 2 0 0 2 0 7 2 2 2 0 3 0 2 0 3 0 2 5 2 0 0 1 0 1 2 6 6 0 4 2 3 1 0 12 15 0 1 9 2 2 1 1 1 1 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 4 4 5 5 6 6 7 9 9 12 14 15 ** Skip Median: 1
* alpha # 16 * Hits: 60
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* Skips >>>>> 11 0 0 5 1 5 0 3 2 0 0 0 1 4 5 4 2 0 0 0 1 3 0 4 1 4 3 4 3 1 0 5 0 1 1 3 5 1 2 19 3 1 1 2 0 2 0 9 0 1 1 0 4 1 0 0 0 4 6 0 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 4 4 4 4 4 4 4 5 5 5 5 5 6 9 11 19 ** Skip Median: 1
* alpha # 17 * Hits: 52
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* Skips >>>>> 0 6 2 0 5 0 5 0 3 4 2 5 2 1 6 1 0 1 1 0 6 6 3 1 2 3 1 2 3 2 2 1 1 3 1 12 6 10 1 3 2 3 0 5 3 4 2 0 2 3 4 5 * Sorted Skips: 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 4 4 4 5 5 5 5 5 6 6 6 6 6 10 12 ** Skip Median: 2

Here are some forecasts for the next 4 draws in the 49's starting Thursday lunchtime (19 July).Each number pair shares the same characteristics and we hope history repeats itself. I used a span of the last 200 draws to make the selection very rigorous and the ideal pair can be difficult to find. The parameters to qualify for selection were very tight. They should never have exceeded their current skips(n) as in n + 4 in the last 200 draws. If history repeats itself then we should have 100% strike rate and I am therefore smarter than my dog, Sam. Who shall win human vs canine? We shall know Friday evening.



* bravo # 19 * Hits: 51 (number pair 5, 25)
------------------------
* Skips >>>>> 7 2 3 7 1 7 5 7 2 6 9 2 1 9 1 0 5 1 0 9 4 7 1 0 1 2 1 0 0 1 1 2 1 0 2 1 3 5 4 0 1 2 3 1 10 3 1 7 0 0 0 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 4 4 5 5 5 6 7 7 7 7 7 7 9 9 9 10 ** Skip Median: 2


* charlie # 16 * Hits: 55 (number pair 16, 22)
------------------------
* Skips >>>>> 8 1 1 4 3 0 4 7 0 0 9 1 9 10 0 0 2 2 3 8 6 1 0 3 0 2 6 0 3 2 0 1 9 0 6 0 3 0 3 3 2 0 3 0 2 1 2 0 2 5 0 2 3 3 0 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 4 4 5 6 6 6 7 8 8 9 9 9 10 ** Skip Median: 2

* echo # 9 * Hits: 43 (number pair 22, 37)
------------------------
* Skips >>>>> 12 2 5 0 0 11 1 9 3 4 6 6 1 2 1 4 1 6 1 7 14 0 3 2 0 1 3 0 12 0 2 1 2 0 6 0 4 1 0 10 6 3 0 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 2 2 2 2 2 3 3 3 3 4 4 4 5 6 6 6 6 6 7 9 10 11 12 12 14 ** Skip Median: 2

------------------
* Foxtrot # 1 * Hits: 56 (number pair 1, 2)
------------------------
* Skips >>>>> 12 4 3 0 0 3 6 1 2 0 9 0 1 6 1 0 3 8 3 1 0 0 1 1 0 1 0 0 1 1 2 1 1 2 2 9 1 11 5 1 4 2 0 5 0 2 1 0 0 14 3 2 3 1 0 1 * Sorted Skips: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 3 3 4 4 5 5 6 6 8 9 9 11 12 14 ** Skip Median: 1

Glad to have somebody promoting a new theory to improve the chances for winning a 6/49 lottery. But in order for me to better understand your theory, I have a few questions that may clarify some points (and this may be true for others also).

First you say: I assume that your alpha number (01 to 24) are meant to represent all 49 numbers in a 6/49 lottery. With 49 numbers, there are 1,176 possible pairs of numbers. But how do you assign pairs of numbers to each alpha number? By sequential order: alpha01 = 01-02, alpha02 = 03-04 to alpha24 = 47-48-49. By frequency: alpha01 = the most frequent pair, alpha02 = the next most often pair without any repeating number, etc. By individual frequency distribution: alpha01 = the 2 most frequent numbers since the last X draws and so on up to alpha24 having the 3 numbers occuring the least often in the last X draws. By skip factor: with alpha01 with the 2 numbers having not been dranw for the longest period, etc. By random selection, why not it may be as good as any other pair.

The alpha group(or bravo or charlie or whatever) represents 24 pairs or sets from the 49 numbers. I randomly assign the pairs to each alpha number. They have absolutely nothing to do with frequencies, just whatever catches my fancy.I even have one group using consecutive numbers(as 1, 2) (3, 4) (5,6) etc.What is inportant is that in each group a number can only be assigned once in that group and no pair must repeat in that group or any other group. The actual skips or frequencies are calculated by MDIED statistics(stats) application. At the moment I have 12 groups althoughI find three or four of them more than enough at the moment. Basically these alpha, bravo etc numbers are pseudo numbers or could even be called fuzzy numbers or fuzzy sets. They do not represent a precise number but an approximation. What interests us is their historical behaviour in the form of skips. Every number whether real or fuzzy has a skip value. In the 6/49 draw on average 3 real numbers have a skip of six and under, 2 numbers have a skip value from 7 to 12 and one with a skip value of 12+. Anyone who picks all their numbers with a skip value of 6 and under has no chance . Same if they pick all their numbers with skip values from 7 to 12 or all numbers from 12+. They have absolutely no chance. So skips are vitally important, a fact that is ignored by most lottery players. We are using skips in Sangoma to find out if a pair or set of numbers will hit in the next 4 draws. This is what I am doing at the moment. It is an improvement on making the isolator more accurate. Later on I will show how skips and the median can help us to find out when the number set(or pair) will hit. Will it be in the next draw or the second, third or fourth draw?

Thank you for your quick and precise answer on your pair choosing method for the alpha numbers. It is easy to understand (and also to apply), it is fast and requires no complex calculations to make. Just follow your nose or whatever catches your fancy. Although this could lead to results as good as Quik Picks but let's not get too far ahead yet.

Then you say:

With 49 numbers, it is surprising to come up with round numbers such as 50% and 75% but stranger things have happened (like somebody winning the jackpot). But my questions relate more to the actual values you quoted.

First, when you say that the alpha numbers will hit in 4 draws, what do you mean? Which of the alpha numbers do you mean, all the 24 alpha number together (with the 49 numbers) or only a certain numbers of them (and which ones then)?

Second, when you say a hit for an alpha number, do you mean both numbers (that make up an alpha number) will hit or at least one of the two numbers in the chosen pair. If I follow your dog Sam example, I should assume he has a pretty good nose to pick up THE ball with THE one pair of numbers that WILL come out in the next 4 draws. I find it surprising that his chances are as good as 75%. Do you have any hard data (based on probabilities) supporting this. In the next 4 draws, there will be 60 pairs of numbers that could be made up, since with the 6 winning numbers in a draw, 15 pairs can be made up while there are always 1176 pairs possible form 49 numbers.

Am I following your theory up to now, or is it back to the starting block?

Hi Springbok,
Thank you for your interesting articles. This method seems like a logical extension to your Isolator research.
What I have done, is to make 50 sets of these alpha pairings, the pairings are randomly done by the computer on each run. All the pairings last skip values are compared against the median and if higher, the difference is added to both balls' weight.
I have done similar for 4-ball sets and 5-ball sets (I'm using the New Zealand 40 ball Lotto so it was logical)
I treat the bonus ball as a valid ball thus working with the equivalent of a 7 ball draw so it is taken into account for these skip stats.

After sorting the balls by their weight, I take the top 9 and the last 7 and am pleased to say that I'm getting a consistent 4,5,6 and even all 7 balls being selected in the total 16.
The reason that I take the last 7 usually one ball from the previous draw comes through as well.
Once again, Well Done!!

Regards
Patrick

*First of all Quick Piks ia a random process. I(hopefully) use statistical analysis based on the performance on previous history and therefore is less than random. Sam is a Quick Picker and I am not.
* The median of 50% can be easily checked by looking at the end of the stats report produced by MDIED. All 6/49 lotteries around the world will show a median of 6. In the same way all favourites in horse races around the world win on average 33% of the time.
* I cannot remember how I came to the figure of 75% of all alpha numbers hit in 4 draws. I probably made a theoretical calculation. I will check this more thoroughly using real time draws. For the moment check these 3 segments which I pulled out of my alpha type draws.

group A
7 2 23 12 2 8 24
1 6 12 2 21 14 5
7 5 23 22 15 10 14
11 1 24 7 1 10 4

Group B
11 13 4 10 9 12 3
1 24 10 20 24 17 18
19 7 1 10 12 24 23
19 13 24 18 20 11 3

Goup C
6 19 7 10 12 24 23
7 20 16 12 2 23 17
11 1 1 22 21 14 5
15 15 8 24 3 4 3

Group A has 7 out of the 24 numbers not appearing in the last 4 draws. Group 2 has 9 numbers failing and Group C has 4 numbers failing. On average around 7 numbers fail to hit-this is around the 75% mark. Sam's luck in picking the winning ball within the next 4 draws will depend on which scenario he is entering in. On average he will get a 75% strike rate but in each individual 4 draw session the strike rate will vary. In a group 2 scenario he might not do so well, do very well in a group 3 scenario, and do averagely well on a group 1 scenario. I think that people who have used the grids in isolators and encounter a losing isolator probably are hitting a group 2 scenario. I would go as far as to say that the group 2 scenario emerges 20% of the time. The group 2 scenario is like a ship encountering a huge rogue wave in a storm-they don't happen often but when they do you know all about it.

*When I say an alpha number hits it will be either one or the other, not both together. So say alpha12(7, 22) hits it means that either 7 or 22 hits and not both together. Of course on rare occasions they can hit simulataneously but this event is not in our calculations.
* To cover all 1176 2 number sets will need around 49 different unique files. To analyse this huge amount of data will need a computer programme to pull out the pseudo type numbers which meet certain parameters. For my modest requirements picking a few files out of 12 is sufficient at the moment. Maybe Patrick123 is on the right track with his method of generating number pairs.

Hi Springbok,
I've played around with various size number sets and have found for the weighting method that using a minimum of at least 50 of these sets adds in that one extra number, so on selecting the top 9, I hope to get at least 4 numbers.

I then try and filter any number from the last draw that was drawn at least 3 times in the last 4 draws or twice consecutively.

I've done this run for the NZ lotto for(21 July 2007) off 80 number sets. Here are the weights:

16 427
21 399
37 393
26 385
31 381
05 360
08 348
19 343
39 336
24 325
11 323
04 319
17 305
07 292
03 281
09 280
15 280
10 256
29 247
35 235
30 223
33 219
02 200
23 182
32 170
28 161
40 159
25 90
13 86
20 82
34 79
01 77
14 74
18 2
06 1
12 1
22 1
27 1
36 1
38 0

Of these, I would take the top 9 and bottom 7, skipping 38.

Regards
Patrick

On second thoughts, after looking at the sorted list, It would suite me better to take the top 10 and only the bottom 6 as 14 statistically,should not come into play.

Regards
Patrick

Sawubona Patrick123

That's the way to go, experiment and check ideas on the computer and see what happens. I see you are using real numbers in your weightings. Intriguing I must say. Will have a look at at that. So far one of the four number sets hit at lunchtime. Now if there is one thing I like is when a number pair is a creature of habit it makes me have warm fuzzy feelings towards them. Foxtrot1 is top of the pops and the moment. Eventually we have to build up into hitting multiple strikes in the same draw. In a 6/49 lottery, there are 6 slots to fill up with 2 number sets. If you can do that then you are within striking distance of hitting the big prize. Hitting 3 slots I have done quite often, even hitting 4 slots once in a while. So it is feasable. Perhaps I need a real sangoma for the other 2 slots . Perhaps I should take a trip to Zululand sometime.

alles van die beste

Here is an intriguing possibility. Out of the 4 predicted sets of numbers to hit in the next 4 draws one has already hit. Supposing none of the surviving three hit in the next 2 draws, would they hit in the fourth draw simultaneously?

Hi Springok,

Yep, After using your system, when I convert back to the real numbers, both numbers in that particular pair would get that weight added to it. Your system seems extremely efficient of selecting the due balls. The other 2 balls are usually from the last 3 draws (89% of the time) and they are the ones that we need the real sangoma for. At this stage I usually eliminate any that have already shown up twice within the last 4 draws and select based on the balls individual hit/skip performance.
I will modify my code to cater for 49 numbers including or excluding the bonus ball, & send you a copy.

Baie Dankie,
Patrick

I am thinking of using sangoma to predict the star numbers in the euro lottery. I have never been able to get a grip on these numbers and unless I do my fantasy of becoming a rand billionaire remains just as a fantasy. This weekend I will try and figure out how to port sangoma into these wretched numbers and run tests to see what gives.